DavinciCodeFactory

斐波那契的问候

# 斐波那契的问候:万物皆数,万物皆递归 def f(n): return n if n <= 1 else f(n-1) + f(n-2) # 黄金比例 $\phi \approx 1.618$ 在迭代中苏醒 greeting = ''.join(chr(64 + f(i)) for i in r

Administrator Administrator 发布于 2026-05-18